Harriet HIGMAN

1870 -

• Name	Harriet HIGMAN  [1, 2, 3, 4]
  Birth	12 Jun 1870	Carlisle, Cumberland, England   [1, 2, 3, 4]
  Gender	Female
  1901 Census	31 Mar 1901	6, Blackhall Street, Carlisle, Carlisle Botchergate, Cumberland, England   [1]
  	Relationship: Wife
  1911 Census	1911	31, Adelaide Street, Carlisle, Cumberland, England   [3]
  1921 Census	19 Jun 1921	Bellevue Crescent, Clifton, Bristol, Gloucestershire, England   [2]
  	Relationship: Wife
  1939 Register	1939	17, Regent Street, Bristol, Gloucestershire, England   [4]
  Person ID	I29636	Ordnance Survey People
  Last Modified	2 May 2026

  
  

  Family	John Purdy HIGMAN,   b. 1 Jan 1869, Plymouth, Devon, England d. 15 Dec 1954, Weston-super-Mare, Somerset, England (Age 85 years)
  Children	1. Daisy Ethel HIGMAN,   b. 1892, Carlisle, Cumberland, England  [Father: natural]  [Mother: natural]   2. Gladys Millicent HIGMAN,   b. 1899, Carlisle, Cumberland, England  [Father: natural]  [Mother: natural]   3. Gertrude Constance HIGMAN,   b. 1901, Carlisle, Cumberland, England  [Father: natural]  [Mother: natural]
  Family ID	F6163	Group Sheet  |  Family Chart
  Last Modified	2 May 2026

  
  

• Sources

  Details: 1901 Census. Details: 1921 Census. [S47] Ancestry.com, 1911 England Census, (Name: Online publication - Provo, UT, USA: Ancestry.com Operations, Inc., 2011.Original data - Census Returns of England and Wales, 1911. Kew, Surrey, England: The National Archives of the UK (TNA), 1911. Data imaged from the National Archives, London, England.;), The National Archives of the UK (TNA); Kew, Surrey, England; Census Returns of England and Wales, 1911. Record for John Purdy Higman https://search.ancestry.co.uk/cgi-bin/sse.dll?db=2352&h=37431717&indiv=try [S194] Ancestry.com, 1939 England and Wales Register, (Name: Ancestry.com Operations, Inc.; Location: Lehi, UT, USA; Date: 2018;), The National Archives; Kew, London, England; 1939 Register; Reference: RG 101/4978B. Record for John P Higman https://search.ancestry.co.uk/cgi-bin/sse.dll?db=61596&h=44431870&indiv=try